Y=6x^2-12+5

Solution for Y=6x^2-12+5 equation:

=6Y^2-12+5

We move all terms to the left:

-(6Y^2-12+5)=0

We get rid of parentheses

-6Y^2+12-5=0

We add all the numbers together, and all the variables

-6Y^2+7=0

a = -6; b = 0; c = +7;
Δ = b2-4ac
Δ = 02-4·(-6)·7
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{42}}{2*-6}=\frac{0-2\sqrt{42}}{-12}
=-\frac{2\sqrt{42}}{-12}
=-\frac{\sqrt{42}}{-6}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{42}}{2*-6}=\frac{0+2\sqrt{42}}{-12}
=\frac{2\sqrt{42}}{-12}
=\frac{\sqrt{42}}{-6}
$